Question

Total no. Of atom in 196amu H2SO4 are

Answer 1

hope it helps u......

Answer 2

1 amu = 1.66×10^-27g
therefore ,
196 = 1.66×10^-24 × 196 g = 325.36×10^-24 g

molar mass = 2+32+64 = 98g/mol

number of moles
= mass/molar mass
= 325.36×10^-24 g/98 gmol^-1
= 3.32 ×10^-24 mol

one mol of any substance contains Avogadro number of molecules .

molecules = no.of moles ×6.022×10^23
atoms = atomicity × no.of moles ×6.022×10^23
atoms = 7 × 3.32 × 10^-24 ×6.022 ×10^23
atoms = 139.96 × 10^-24+23
atoms = 139.96 × 10^-1
atoms = 13.996

the exact answer is 14 because 98 amu contains 7 atoms therefore 196(98×2) must contains 7×2=14 atoms .

Then question exist why my answer did not come correct because I am take approximate value like avogadr number etc