Total no. Of atoms in 294g of sulphuric acid
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We know that : Formula for Sulphuric Acid is : H₂SO₄
⇒ One Mole of H₂SO₄ weighs : (2 + 32 + 64) = 98 grams
⇒ 3 Moles of H₂SO₄ weighs : (3 × 98) = 294 grams
But, One Mole of H₂SO₄ Contains : 6.023 × 10²³ Molecules of H₂SO₄
294 grams of H₂SO₄ Contains : 3 × 6.023 × 10²³ Molecules of H₂SO₄
⇒ 294 grams of H₂SO₄ Contains : 1.8 × 10²⁴ Molecules of H₂SO₄
But, One Molecule of H₂SO₄ contains : (2 + 1 + 4) = 7 Atoms
⇒ 294 grams of H₂SO₄ Contains : 7 × 1.8 × 10²⁴ Atoms
⇒ 294 grams of H₂SO₄ Contains : 1.26 × 10²⁵ Atoms
Answered by
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Molar mass of H2SO4 = 1×2 + 32 + 16×4
Molar mass of H2SO4 = 98g/mol
Moles of H2SO4 = mass/molar mass
Moles of H2SO4 =294/98
Moles of H2SO4 = 3mol
Moles of H2SO4 = Number of molecules of H2SO4 / Avagadro number
Number of molecules of H2SO4 =Moles × Avagadro number
Number of molecules of H2SO4 = 3 ×6.023×10^23
Number of molecules of H2SO4 = 18.069 ×10^22
Now .....
In one molecule of H2SO4 there are 7 atoms
So......
In 18.069×10^23 number of atoms will be
18.069×10^23 × 7
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