Total no. of atoms of all element present in 1 mol of ammonium dichromate is?
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1.14 × 10²⁵ is the answer if you are looking for explanation then please do ask me in the comments
Well here is your explanation
We know for 1 mol of Ammonium Dichromate we have:
(1×2) 2 mol Nitrogen,(4×2) 8 mol Hydrogen,2 mol Chromium,7 mol Oxygen.
Multiply these by Avogadro’s constant (6.02 × 10^23) and that will be the number of atoms for each element in one mole of ammonium dichromate. and then add them all. It's the result.
shubhambajpai865:
How explain it
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0
1.44x10^25 atoms are present
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