Question

total no. of atoms of all elements present in 1 mole of ammonium dichromate( NH4)2 cr2o7) is

Answer 1

total atoms = 19 × NA (6.022×10^23)

Answer 2

Answer: Atoms present in 1 mole of ammonium dichromate of

1. $Nitrogen=12.044\times 10^{23}atoms$
2. $Hydrogen=48.176\times 10^{23}atoms$
3. $Chromium=12.044\times 10^{23}atoms$
4. $Oxygen=42.154\times10^{23}atoms$

Explanation: Elements present in $(NH_4)_2Cr_2O_7$ are Nitrogen, Hydrogen , Chromium and oxygen.

We are given 1 mole of ammonium dichromate and we need to find the number of atoms of all the elements present in it.

According to the mole concept,

1 mole of a substance contains $6.022\times 10^{23}$ atoms.

• Atoms of Nitrogen present in 1 mole of Ammonium dichromate = $2\times 6.022\times 10^{23}=12.044\times 10^{23}atoms$

• Atoms of Hydrogen present in 1 mole of Ammonium dichromate = $8\times 6.022\times 10^{23}=48.176\times 10^{23}atoms$

• Atoms of Chromium present in 1 mole of Ammonium dichromate = $2\times 6.022\times 10^{23}=12.044\times 10^{23}atoms$

• Atoms of Oxygen present in 1 mole of Ammonium dichromate = $7\times 6.022\times 10^{23}=42.154\times 10^{23}atoms$