total no. of atoms represented by the compound cuso4.5h2o is
Answers
Answered by
5
total no. of atoms present in compound CuSO4.5h2o is 13
explaination ---------
1 atom of Cu + 1 atom of S + 4 atom of O + 10 atom of H + 5atom of O
= 1+1+4+10+5
= 21
HOPE!!!!! It works......
explaination ---------
1 atom of Cu + 1 atom of S + 4 atom of O + 10 atom of H + 5atom of O
= 1+1+4+10+5
= 21
HOPE!!!!! It works......
banduWasnik:
wrong
how ?
what is the answer ?
21
can u explain , how ?
give me explaination if you got yur answer
cu = 1 sulphur =1 oxygen atoms =4+5=9 hydrogen atoms =10 total atoms = 1+1+9+10=21
ohh yeah . i missed that
thnku
Answered by
5
Total number of atoms in CuSO4⋅5H2O are
1+1+4+5(2+1)=6+5×3=21
∴CuSO4⋅5H2O has 21 atoms.
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