total no. of electron in 18ml. of water
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18 mL water X 1 g/mL = 18 g water
moles H2O = 18 g / 18 g/mol = 1 mole H2O
Number of H2O molecules = 1 mol X 6.02X1023 molecules/mole= 6.02X1023molecules
Total electrons in 1 H2O molecule = 10 electrons/molecule
So, 6.02 X 1023 molecules X 10 electrons/molecule = 6.02 X 1024 electrons
6.02 X 1024 electrons are present in 18mL of water.
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moles H2O = 18 g / 18 g/mol = 1 mole H2O
Number of H2O molecules = 1 mol X 6.02X1023 molecules/mole= 6.02X1023molecules
Total electrons in 1 H2O molecule = 10 electrons/molecule
So, 6.02 X 1023 molecules X 10 electrons/molecule = 6.02 X 1024 electrons
6.02 X 1024 electrons are present in 18mL of water.
hope it helps you
plz Mark as brainiliest answer
anuj176:
thanks
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Moles of water = mass/molar mass = 18/18 = 1.
1 mole of water contains = NA molecules.
Total electrons in water = 2(H) + 8(O) = 10.
1 molecule of water contains = 10 electrons
1 mole of water contains = NA molecules.
Total electrons in water = 2(H) + 8(O) = 10.
1 molecule of water contains = 10 electrons
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