Total no of electron neutron and proton in 14 mg of C
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12 g of C has 6 ×Na p and 6×Na n
So, 14 mg will have..
7/6 × 6.022 × 10^20 protons and neutrons
So, 14 mg will have..
7/6 × 6.022 × 10^20 protons and neutrons
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