total no of electron present 18ml of water
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1ml of water =>1×2+16=18amu
1mole of water contains 18 amu
18 ×Å=18×6.022×10^23
=>1.08e are present in 18 ml of water
1mole of water contains 18 amu
18 ×Å=18×6.022×10^23
=>1.08e are present in 18 ml of water
haris112:
am i right
ss
ohh kk, ✌️
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