Question

total no of electron present in 18ml of water (density of water is 1gm L')

Answer 1

Since density of water is 1 gm/cc, 18 ml corresponds to mass m =18 g of water.

so, no. of moles corresponding to 18 g = m/A = 1, where  A is molecular wt (water =18 g)

Now, 1 mole of water contains 6.022*10^23 molecules of H2O and

one molecule of H2O contains 10 electrons (i.e. There are 8 electrons in oxygen and 1 from each hydrogen so a water molecule has 10 electrons).

Hence, total no. of electrons present in 18 ml of water =10 * 6.022*10^23

   = 6.022*10^24

hope it helps you!!!!!
:)

Answer 2

Answer:

Explanation:Answer: in normal temperature 18 ml water = 1 mole water. each mole of water contains 6.023x10^23 molecules of water and 1 molecule of water contains 10 etectron.