Total no. of electrons in 0.5 mol of sulphate ions
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The number of particle = mole x Avogadro no
= 0.5 x 6.02x10^23
=3.01x10^23
no of electron present in one molecule = 16 + 4[8] -[-2]= 50
no of electrone present in 3.01x 10^23 = 3.01x 10^23 x 50
=15.01 x 10^23
=1.5 x10^ 24
91priya:
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