Question

Total no. of electrons in 0.5 mol of sulphate ions
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Answer 1

The number of particle = mole x Avogadro no

= 0.5 x 6.02x10^23

=3.01x10^23

no of electron present in one molecule = 16 + 4[8] -[-2]= 50

no of electrone present in 3.01x 10^23 = 3.01x 10^23 x 50

=15.01 x 10^23

=1.5 x10^ 24