total no of favourable outcomes (sum > 11) =
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Answer:
So, the number of favourable outcomes is 11. We know that the number of possible outcomes is 36. Thus, the probability of getting a multiple of 2 on one dice and multiple of 3 on the other dice is =1136. (d) We will calculate the probability of getting a multiple of 3 as a sum of digits on both the dice..
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Hey...✌✌
Here's your answer...⏬⏬
Step-by-step explanation:
Favourable outcomes for a multiple of 2 on one dice and a multiple of 3 on the other side are:
(2,3);(2,6);(3,2);(3,4);(3,6);(4,3);(4,6);(6,2);(6,3);(6,4);(6,6)
Number of favourable outcomes =11
Hence,the probability of getting a multiple of 2 on one dice and a multiple of 3 on the other dice =
36/11✅✅
Hope It Helps...☺
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