Question

total no. of ions present in 1L of 3M
aqueous solution of LaCl3

Answer 1

Answer:

Number of moles of the compound =2×0.8=1.6

Number of ions per mole =5

Hence, number of ions =1.6×5×6×10

23

=4.8×10

24

Explanation:

Number of moles =molarity×volume

                             =0.1×0.001

x=10

−4

  moles or 0.0001 moles

Ba(NO

3

​

)

2

​

⟶Ba

2+

+NO

3

​

 

2−

The total number of ions = 3 ions in one mole of Ba(NO

3

​

)

2

​

.

So, in 10

−4

 moles = 3×6.023×10

23

×10

−4

= 3.0×6.02×10

19