total no of lines in H-spectrum for transition 5 to 1
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Given
A hydrogen atom, Having n
2
=5 and n
1
=1
Total no of the spectral lines =
2
(n
2
−n
1
)(n
2
−n
1
−1)
Here n
2
=5 and n
1
=1
Therefore the total no of the spectral line
2
(5−1)(5−1−1)
=
2
20
=10
So, the ten lines is
5→4,5→3,5→2,5→1,4→3,4→2,4→1,3→2,3→1,2→1 are
possible in this case.
Of all this lines only, one's falling in Balmer series are in visible region.
For Balmer series,x=2 and y=3,4,5
Thus,
5→2,4→2,3→2 it shows three lines lie in the visible region.
Explanation:
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