Question

total no. of moles of dilute nitric acid appearing in balanced reaction with copper metal is :​

Answer 1

The total no. of moles of dilute nitric acid appearing in balanced reaction with copper metal is 4

Explanation:

The balanced reaction is:

$4HNO_3+Cu\rightarrow Cu(NO_3)_2_2NO_2+2H_2O$

From this equation it is clear that with 1 mole of copper metal, 4 moles of $HNO_3$ reacts

Therefore, the total no. of moles of dilute nitric acid appearing in balanced reaction with copper metal is 4

Hope this answer is helpful.

Answer 2

Answer:

4 moles

Explanation:

When copper is reacted with nitric acid, the result is the formation of copper nitrate salt that forms is a deep blue color.

In order to find out the number of moles of each reactant, we first need to write the chemical equation in balanced form;

4 HNO3(l) + Cu(s) ==> Cu(NO3)2(s and aq) + 2 NO2(g) + 2 H2O(l)

From the equation we can see that if we have one mole of copper then we need 4 moles of nitric acid for a complete reaction