Chemistry, asked by lokesher, 11 months ago

total no. of orbitals in a shell are 16,find total no. of orbitals which have m=0 in that shell.
options
(a)4,(b)2,(c)8,(d)6​

Answers

Answered by siddhantp2020
1

Answer:

4

Explanation:

number of orbital in a shell is n^2 .

n=4 because 4^2=16

Answered by DeenaMathew
2

The total no. of orbitals which have m=0 in that shell is (a)4.

  • The total number of orbitals is 16.
  • Orbitals are calculated by the formula
  •  {n}^{2}
  • Here, n= shell number. so, n² = 16
  • Now,
  • n =  \sqrt{16}  = 4It means the shell is 4. and for n = 4, subshells can be 4s, 4p, 4d and 4f.
  • m = 0 is for 4s, 4p, 4d and 4f and these are a total of 4 subshells.

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