Question

Total no of tiger & peacock in zoo is 60 the total number of their legs is 160 find tiger & peacock

Answer 1

$\sf\large\underline{Let:}$

$\sf{\implies Number\:_{(tiger)}=x}$

$\sf{\implies Number\:_{(peacock)}=y}$

$\sf\large\underline{Given:}$

$\sf{\implies Total\:Number\:_{(tiger+peacock)}=60}$

$\sf{\implies Total\:Number\:_{(legs)}=160}$

$\sf\large\underline{To\: Find:}$

$\sf{\implies Number\:_{(tiger\:and\: peacock)}=?}$

$\sf\large\underline{Solution:}$

• As we know tiger has 4 legs and peacock has 2 legs here we also assume that x is the number of legs for tigers and peacock for y than setting up equation]

$\sf{\implies Total\:Number\:_{(tiger+peacock)}=60}$

$\rm{\implies x+y=60-----(i)}$

$\sf{\implies Total\:Number\:_{(legs)}=160}$

$\rm{\implies 4x+2y=160-----(ii)}$

• Here in eq 1st multiplying by 4 than subtracting from eq 2]

$\rm{\implies 4x+4y=240}$

$\rm{\implies 4x+2y=160}$

• By solving we get here]

$\rm{\implies 2y=80}$

$\rm{\implies y=40}$

• Now calculate the number of tigers after putting the value of y=40 in eq 1]

$\rm{\implies x+y=60}$

$\rm{\implies x+40=60}$

$\rm{\implies x=60-40}$

$\rm{\implies x=20}$

$\sf\large{Hence,}$

$\sf\orange{\implies Number\:_{(tiger)}=20}$

$\sf\blue{\implies Number\:_{(peacock)}=40}$