Math, asked by akshitgupta16, 11 months ago

total no of ways on which 7 different prizes be awarded to 5 students in such a way that every student should have at least one prize

Answers

Answered by GulabLachman
1

Answer:

5⁷ = 78125 Ways

Step-by-step explanation:

This is a sum from the chapter permutation and combination.

Given the number of prizes = 7, Number of Students = 5

So, there are seven different prizes and five different students. It has to be divided in such a manner that each student gets atleast one prize. So each prize comes on with a list of Seven students.  When the judge awards first prize she chooses from the group of 7 students , again when she gives the second she chooses from the group of 7 so the series goes like

5 * 5 * 5 *5 *5 * 5 * 5 = 5⁷ ways

Which is equivalent to 78125 ways.

Similar questions