Question

Total number of 1° alcohol with formula c4h10o (only structural isomer) is

Answer 1

Start with four carbons in a row and put an
OH
group in every possible position.
This gives us
1.
CH
3
CH
2
CH
2
CH
2
OH
, butan 1-ol
and
2.
CH
3
CH
2
CH(OH)CH
3
, butan-2-ol
Now use a 3-carbon chain with a
CH
3
on the middle carbon.
This gives
(
CH
3
)
2
CHCH
2
OH
, 2-methylpropan-1-ol
and
(
CH
3
)
3
COH
, 2-methylpropan-2-ol.
Now for the ethers.
Let's start with five atoms in a row.
This gives
CH
3
CH
2
CH
2
OCH
3
, 1-methoxypropane
and
CH
3
CH
2
OCH
2
CH
3
, ethoxyethane
Finally, the only choice for a branched-chain ether is
(
CH
3
)
2
CHOCH
3
, 2-methoxpropane.
And there are your seven isomers of
C
4
H
10
O

Answer 2

Answer:

The no of 1° alcohol in C4H10O is 2

In isomerm

CH3 CH2 CH2 CH2 OH; butan -ol

( CH3 )2 CH CH2 OH ;

2-methyl propane -ol