Total number of atom present in 64g of so2
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Molecular mass of SO2 :
= 32+2x16 = 64U
∴ Molar mass is 64g
1 mole of SO2 [64g of SO2] contains 6.022x 10²³ atoms.
= 32+2x16 = 64U
∴ Molar mass is 64g
1 mole of SO2 [64g of SO2] contains 6.022x 10²³ atoms.
Answered by
28
Solution:
First you have to find the number of moles of SO₂, and this is done by;
Finding the molar mass of SO₂ (S=32, O =16) hence the molar mass is 32+16*2 =64.
Once you have the molar mass and mass you can now find moles.
Moles= mass/molar mass
64/64 = 1
So the number of moles of SO₂ is 1 mole
For you to get the number of atoms it has having gotten moles, you'll use Avogadro number.
Avogadro number = 1 mole = 6.023*10²³
So if 1 mole = 6.02*10²³ atoms
what of 1 mole of SO₂ = 1× 6.023 atoms
Hence SO₂ has 6.023 ×10²³ atoms.
First you have to find the number of moles of SO₂, and this is done by;
Finding the molar mass of SO₂ (S=32, O =16) hence the molar mass is 32+16*2 =64.
Once you have the molar mass and mass you can now find moles.
Moles= mass/molar mass
64/64 = 1
So the number of moles of SO₂ is 1 mole
For you to get the number of atoms it has having gotten moles, you'll use Avogadro number.
Avogadro number = 1 mole = 6.023*10²³
So if 1 mole = 6.02*10²³ atoms
what of 1 mole of SO₂ = 1× 6.023 atoms
Hence SO₂ has 6.023 ×10²³ atoms.
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