Total number of atoms in 0.5 moles of potassium dichromate
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3.011x10^23 how to find such type of questions
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One (K2Cr2O7) Potassium dichromate molecule contains total 11 atoms (2+2+7).
So, number of atoms in
0.5 mole = 0.5×nA
= 0.5×(6.022×10^23)
= 3.011×10^23 atoms
So, number of atoms in
0.5 mole = 0.5×nA
= 0.5×(6.022×10^23)
= 3.011×10^23 atoms
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