Question

total number of atoms present in 160 amu of oxygen element is​

Answer 1

6.02×10
23

Moles of O
2
​
=
32
16
​
=
2
1
​

Number of molecules =
2
1
​
×N
A
​

Number of atoms = 2×
2
1
​
×

Answer 2

Given:

Mass of oxygen element=160 amu

To find:

The total number of atoms present

Solution:

We can find the number by following the given process-

We know that the number of moles can be calculated by dividing the given mass of an element by its atomic mass.

The mass of the oxygen element=160 amu

The atomic mass of oxygen=16 amu

The number of moles= Mass of oxygen/Atomic mass of oxygen

=160/16

=10 mol

1 mol= 6.022×10²³

So, 10 mol of oxygen will have 6.022×10²³×10 atoms

The number of oxygen atoms= 6.022×10²⁴

Therefore, the total number of atoms present in 160 amu of oxygen is 6.022×10²⁴.