Question

Total number of atoms present in 170g of Ammonia(NH3)​

Answer 1

Answer:

Explanation:

Mass of 1 mol or (6.022×10  

23

 molecules) of NH  

3

​  

=14+3×1=17 g

Number o f molecules in 34 g NH  

3

​  

=  

17

34

​  

×6.022×10  

23

=12.044×10  

23

 

Number of atoms present in 1 molecule of NH  

3

​  

=4

Number of atoms in 34 g NH  

3

​  

=4×12.044×10  

23

 

                                                     ≈48×10  

23

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