Question

Total number of atoms present in 17g of NH3

Answer 1

Molecular mass of Ammonia = 17 g

17 g of Ammonia contains 6.022 × 10^23 molecules of Ammonia

Number of atoms = Atomicity × Number of molecules
= 4 × 6.022 × 10^23
= 24.088 × 10^23

∴ Total number of atoms in 17 g of NH3 is 24.088 × 10^23

Answer 2

Answer:

$17 \mathrm{~g}$ of ammonia contains $6.022 \times 10^{23}$ molecules.

Explanation:

Given: 17g of NH3

To find: The number of molecules of ammonia in 17 g ammonia

Step 1: The molar mass of ammonia $=17 \mathrm{gmol}^{-1}$

Given the mass of water $=17 \mathrm{~g}$

Number of moles $=\frac{\text { Given mass of molecule }}{\text { Molecular mass of water }}$

Step 2: Number of moles ammonia $=\frac{17}{17}=1$ mole

Hence the number of mole of ammonia is 1.

1 mole of ammonia $=6.022 \times 10^{23}$ molecules

Step 3: Hence, $17 \mathrm{~g}$of ammonia contains $6.022 \times 10^{23}$ molecules.

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