Question

Total number of atoms present in 34 g of NH3 is
(a) 4x 1023
(b) 4.8 x 1021
(c) 2 x 1023
(d) 48 x 1023​

Answer 1

Answer:

No. Of Moles =given weight /atomic

mass

Atomic mass of NH3=17g

=34/17=2 moles

1mole=6.022 * 10^23 atoms

2 moles =2*6.022*10^23

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