Question

Total number of atoms represented by the compound CuSO4.5H2O is :
(A) 20
(B) 21
(C) 6
(D) 10
With full explanations please ​

Answer 1

Answer:

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Explanation:

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Answer 2

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Ans - C) 21 atoms

$~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~$

Explanation:

Compound = $\bold{CuSO_4 . 5H_2 0}$

1. First Element = Cu (Copper)

No. of Cu atoms = 1

2. Second Element = $S$ (Sulphur)

No. of S atoms = 1

3. Third Element = O (Oxygen)

No. of O atoms = 4 + 5 = 9

4. Fourth Element = H (Hydrogen)

No. of H atoms = $5 \times 2 =$ 10

Total number of atoms = 1 + 1 + 9 + 10 = 21