Question

Total number of bonds in IF7 which r at 72 degrees​

Answer 1

Answer:

The central iodine atom in IF

7

undergoes sp

3

d

3

hybridization which results in pentagonal bipyramidal geometry.

Each axial F atom forms five 90

o

angles with five equatorial F atoms.

Hence, the total number of ∠FIF angles in IF

7

having the bond angle value of 90

o

is 10

Answer 2

Total number of bonds in IF₇ which are at 72 degrees​ is 5.

• IF₇ is an interhalogen compound.
• Interhalogen compounds are formed when halogens mutually combine together to form a remarkable set of compounds of general formula XYₙ where both X and Y are halogen atoms and n is an integer having values 1, 3, 5 or 7.
• IF₇ is formed by sp³d³-hybridisation of the central atom in its second excited state.
• The molecule has a pentagonal bipyramidal structure.
• Five fluorine atoms are in one plane and one fluorine atom is above the plane and one fluorine is below the plane.
• So, there are five angles with 72 degrees in magnitude and ten angles with 90 degrees in magnitude.