Question

Total number of electron present in 2 mole of Mg​

Answer 1

Mole = 2

Molar mass = 12 g

Total mass = 24 g

No. of atoms of Mg in 2 Mole:

==> 6.022 × 10²⁴ × 2

==> 12.044 × 10²⁴ atoms

No. of protons in 1 atom = 6

So,

No. of electrons in 2 Mole :

==> No. of atoms in 2 Mole × 6

==> 12.044 × 6 × 10²⁴

==> 72.264 × 10²⁴ electrons

Answer 2

Answer:

The total number of electrons present in $2$ mole of Mg is $1.445\times10^{25}$

Explanation:

We know that the atomic number of magnesium is $12$ which means that the number of electrons in magnesium is $12$.

Now for calculating the number of electrons, we multiply the number of moles with the Avogadro number$=2\times 6.023\times 10^{23}$

Therefore the number of electrons present in $2$ mole is$=2\times12\times6.023\times10^{23}\\=24\times6.023\times10^{23}\\=144.552\times10^{23}\\=1.445\times10^{25}$