Question

Total number of electron present in 48gm mg^2+ are

Answer 1

Explanation:

n=w/m

48/24=2 mole

no. of electron= mole ×Avagado no. ×no. of electrons

2×6.02×10^23×12

24×6.02×10^23

144.48×10^23

Answer 2

1.2044 × 10^25

Mg : Z = 12

Mg^2+ : electrons = 12-2 =10

Mg : gm atm wt : 24

Mg : given mass : 48g

moles = given mass / atm wt

moles =n= 48/24 = 2

1 mole = 6.022 ×10 ^23 atoms

1 atom = 10 electrons

2 moles = 2×10×6.022 ×10 ^23

total electrons = 1.2044 × 10^25