Question

Total number of electrons in 6.2 mg NO3- will be??

Answer 1

Answer:

The chemical name of N03- is Nitrate.

It is a polyatomic ion with molecular mass of 62.0049 u.

Number of electrons in 3.1 mg N03- is:

Number of NO3 molecule = 3.1/62 x 6.022 x10^23

 = 3.011x10^22

 Then, total number of electrons in NO3

= 32 electrons

 = 32 x3.011x10^22

Explanation:

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