Total number of electrons in 81 g of A13+ are
(Given : at. no. of Al = 13 and at. mass = 27 u)
(1) 1.806 x 1025 (2) 6.02 x 1024
(3) 1.22 x 1025 (4) 2.347 x 1025
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Answer:
As given Al3+
(Which means has loosed 3 e-mail )
Atomic no.=13
Electron remaining=10
27g=atomic mass
27g of Al3+=10Na
1gof Al3+=10Na/27
81gof Al3+=10*6.02*10^23*81/27=
1.806*10^25
Explanation:
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