Question

Total number of electrons in 81 g of Al3+ are
(Given : at. no. of Al = 13 and at, mass = 27 u)​

Answer 1

Answer : 1.8069 × 10^25

Number of electron in Aluminium element, Al = 13

Now, when we remove three electron from Al it becomes Al³+ ion. and then number of electrons in one Al³+ ion = 13 - 3 = 10....(1)

Now, atomic mass of Aluminium or Al³+ ion = 27 g/mol. [ you should remember that if we remove or add electron to any element, mass number doesn't change. ]

Given mass of Al³+ = 81g

So, number of mole of Al³+ = 81/27 = 3mol

Then, number of Al³+ ions in 3 mol = 3 × 6.023 × 10²³ = 18.069 × 10²³

Now, number of electrons in 18.069 × 10²³ Al³+ ions = 10 × 18.069 × 10²³ [ from equation (1), ]

= 1.8069 × 10^25

❤Hope it will help you.❤

Answer 2

Answer:

Explanation:

Answer : 1.8069 × 10^25

Number of electron in Aluminium element, Al = 13

Now, when we remove three electron from Al it becomes Al³+ ion. and then number of electrons in one Al³+ ion = 13 - 3 = 10....(1)

Now, atomic mass of Aluminium or Al³+ ion = 27 g/mol. [ you should remember that if we remove or add electron to any element, mass number doesn't change. ]

Given mass of Al³+ = 81g

So, number of mole of Al³+ = 81/27 = 3mol

Then, number of Al³+ ions in 3 mol = 3 × 6.023 × 10²³ = 18.069 × 10²³

Now, number of electrons in 18.069 × 10²³ Al³+ ions = 10 × 18.069 × 10²³ [ from equation (1), ]

= 1.8069 × 10^25

❤Hope it will help you.❤