Total number of electrons present in 1.7 g of ammonia is
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Answer ⇒ Option (a). 6.022 ×10²³
Explanation ⇒
1 mole of the ammonia contains 6.022 × 10²³ atoms.
∴ 17 g of the Ammonia contains 6.022 × 10²³ atoms.
∴ 1 g of the ammonia contains (6.022 × 10²³)/17 atoms.
∴ 1.7 g of the ammonia contains (6.022 × 10²³) × 1.7/17 atoms.
= 6.022 × 10²² atoms.
Now, 1 atom of the Ammonia contains 7 + 3 electrons = 10 electrons.
∴ 6.022 × 10²² atoms of the Ammonia contains 10 × 6.022 × 10²² electrons.
= 6.022 × 10²³ electrons.
Hence, the number of the electrons in 1.7 g of the Ammonia is 6.022 × 10²³ electrons.
Hence, the Option (a) is correct.
Hope it helps.
Explanation ⇒
1 mole of the ammonia contains 6.022 × 10²³ atoms.
∴ 17 g of the Ammonia contains 6.022 × 10²³ atoms.
∴ 1 g of the ammonia contains (6.022 × 10²³)/17 atoms.
∴ 1.7 g of the ammonia contains (6.022 × 10²³) × 1.7/17 atoms.
= 6.022 × 10²² atoms.
Now, 1 atom of the Ammonia contains 7 + 3 electrons = 10 electrons.
∴ 6.022 × 10²² atoms of the Ammonia contains 10 × 6.022 × 10²² electrons.
= 6.022 × 10²³ electrons.
Hence, the number of the electrons in 1.7 g of the Ammonia is 6.022 × 10²³ electrons.
Hence, the Option (a) is correct.
Hope it helps.
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Answer:
Total number of electrons present in 1.7g of ammonia is 6.022× 10²³.
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