Question

Total number of electrons present in 1.7 g of ammonia is

Answer 1

Answer ⇒ Option (a). 6.022 ×10²³

Explanation ⇒

1 mole of the ammonia contains 6.022 × 10²³ atoms. 
∴ 17 g of the Ammonia contains 6.022 × 10²³ atoms.
∴ 1 g of the ammonia contains (6.022 × 10²³)/17 atoms.
∴ 1.7 g of the ammonia contains (6.022 × 10²³) × 1.7/17 atoms. 
    = 6.022 × 10²² atoms. 

Now, 1 atom of the Ammonia contains 7 + 3  electrons = 10 electrons. 

∴ 6.022 × 10²² atoms of the Ammonia contains 10 × 6.022 × 10²² electrons. 
   = 6.022 × 10²³ electrons.

Hence, the number of the electrons in 1.7 g of the Ammonia is 6.022 × 10²³ electrons. 

Hence, the Option (a) is correct.


Hope it helps.

Answer 2

Answer:

Total number of electrons present in 1.7g of ammonia is 6.022× 10²³.