Question

Total number of electrons present in 1.7 g of ammonia is
(a) 6.022 x 1023
(b) 6.022 x 1022
(c) 6.022 X 1024
(d) 6.022 x 1023
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Answer 1

It's answer is (a)6.022×1023

no of moles = 1.7/17=0.1. (Molar Mass of nh3=17)

No of ions=0.1×6.022×1023

=6.022×1022

no of electrons=6.022×1022×10

=6.022×1023

Answer 2

Answer:

correct answer is (a)...