Total number of electrons present in 1.7 g of ammonia is
(a) 6.022 x 1023
(b) 6.022 x 1022
(c) 6.022 X 1024
(d) 6.022 x 1023
Answers
Answered by
21
It's answer is (a)6.022×1023
no of moles = 1.7/17=0.1. (Molar Mass of nh3=17)
No of ions=0.1×6.022×1023
=6.022×1022
no of electrons=6.022×1022×10
=6.022×1023
no of moles = 1.7/17=0.1. (Molar Mass of nh3=17)
No of ions=0.1×6.022×1023
=6.022×1022
no of electrons=6.022×1022×10
=6.022×1023
brain393:
thanks a lot
Answered by
6
Answer:
correct answer is (a)...
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