Question

Total number of electrons present in 1.7 g of ammonia is



Ans: 6.022×10^23
Please someone prove it

Answer 1

Answer:

No. of moles of NH3 = 1.7/17 =0.1

Total no. of molecules of NH3 = 0.1 ×6.022×10^23

No. of electrons in one NH3 molecule =7+3×1=10

so total no. of electrons = 10×0.1×6.022×10^23