Question

Total number of electrons present in 1.7 gram of ammonia is

Answer 1

1 mole of the ammonia contains 6.022 × 10²³ atoms.

∴ 17 g of the Ammonia contains 6.022 × 10²³ atoms.

∴ 1 g of the ammonia contains (6.022 × 10²³)/17 atoms.

∴ 1.7 g of the ammonia contains (6.022 × 10²³) × 1.7/17 atoms.

= 6.022 × 10²² atoms.

Now, 1 atom of the Ammonia contains 7 + 3 electrons = 10 electrons.

∴ 6.022 × 10²² atoms of the Ammonia contains 10 × 6.022 × 10²² electrons.

= 6.022 × 10²³ electrons.

Hence, the number of the electrons in 1.7 g of the Ammonia is 6.022 × 10²³ electrons.