Question

Total number of electrons present in 1.7g of ammonia is a, 6.022×10 powerof 23 b, 6.022×10 power of 22by 1.7 c, 6.022×1024by 1.7 d, 6.022×10 power of 23by 1.7

Answer 1

b option..............

Answer 2

hay mate here is your answer

1 gram atom = N – atoms = 6.023 x 1023 atoms = gram atomic weight

gram atomic weight = weight of N atoms in grams

1 gram molecule = N- molecules = 6.023 x 1023 molecules = gram molecular wt.

gram molecular wt. = wt. of N molecules in gram

number of moles of molecules ‘n’ = wt. (gram)/ molecular wt.= w/ m

number of moles of atoms ‘n’ = wt. (gram)/ atomic wt.

no. of moles ‘n’ = no. of particles / ( 6.023 x 1023