Total number of electrons present in 1.8 g of H2O is (a) 0.1 NA (b) 0.01 NA (c) NA (d) 1.1 NA
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Answer:
One molecule of water contains 10 electrons. One mole of water molecules will contain 10N
A
electrons. Here, N
A
is the Avogadro number.
1.8 g of water molecule corresponds to
18
1.8
=0.1 mole. Thus, 0.1 mole of water molecule contains 0.1×10N
A
=N
A
electrons = 6.022×10
23
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