total number of electrons present in 18 ml water
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hlo....dear....here is your answer....✨✨✨✨☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️☺️,
moles of water = mass/molar mass = 18/18 = 1.
1 mole of water contains = NA molecules.
total electrons in water = 2(H) + 8(O) = 10.
1 molecule of water contains = 10 electrons.
hope it helps you...!!!✌️✌️
moles of water = mass/molar mass = 18/18 = 1.
1 mole of water contains = NA molecules.
total electrons in water = 2(H) + 8(O) = 10.
1 molecule of water contains = 10 electrons.
hope it helps you...!!!✌️✌️
parthsuvagia:
wrong
how
see carefully
okkkk then say.... for
this answer
no of electrons in 1 molecule of water =10, thus no of electrons in 6.022*10^23=10*6.022*10^23=6.022*10^24 electrons
answer is 6.022*10^24 electrons
seriously
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total no. of electron present in water=10.
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