Chemistry, asked by Meesharehman, 1 year ago

Total number of electrons present in 34g OHnegative are

Answers

Answered by dattahari09

0

total number of electrons =

mole xNA x10

=34/17xNA. X10

=20NA

=20 x6.022x10^23

= 12.044 x10^24 electrons

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