Question

total number of electrons present in 4 amp current flowing for 1 second is​

Answer 1

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Answer 2

Given :

Current through the conductor , I = 4 A .

Time of flow of current , t = 1 s .

To Find :

Total number of electron present .

Solution :

We know , current is given by :

$I=\dfrac{q}{t}$

Here , q is the charge and t is time .

So , $q=I\times t$              ..... ( 1 )

Putting value of I and t in equation 1  .

We get , $q=4\times 1 = 4\ C$ .

Therefore , total charge is 4 C .

Therefore , number of electrons is given by :

$n=\dfrac{Total\ Charge}{Charge \ on\ one \ electron}\\\\n=\dfrac{4\ C}{1.6 \times 10^{-19}\ C}\\\\n=2.5\times 10^{19}$

So , total number of electrons are $2.5\times 10^{19}$ .

Learn More :

Current and charges

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