Question

Total number of electrons present in 48 g Mg2+ are XNA. Find the value of x.​

Answer 1

can u give me some thanks

10 thanks❤ = 15 thanks❤

20 thanks ❤ = 30 thanks❤

50 thanks ❤ = 50 thanks ❤

100 thanks ❤ = 100 thanks❤

Answer 2

Answer:

24 gm of Magnesium contains=NA​ atoms. Where NA​= 6.023 × 1023

48 gm of Mg contains =2NA​ atoms.

1 atom of Mg contains 12 electrons

Mg2+ ion will contain (12–2)=10 electrons

2NA​ Mg2+ ions will contain

=10×2NA​ electrons

=10×2×6.023×1023

=20NA​

Explanation: