Total number of electrons present in "penultimate" potassium shell of potassium 19 is equal to
Answers
Answered by
0
Answer:
Explanation:
Potassium, having atomic number 19, has the electronic configuration of 2,8,8,1 in the K,L,M,N and so on named shells.
Thus the number of electrons present in it's penultimate i.e, before-last shell, according to the above specified electronic configuration will be
8(Ans).
Similar questions