Math, asked by Sweetyhoty5115, 1 year ago

Total number of four digit odd numbers that can be formed using 0, 1, 2, 3, 5, 7 (using repetition allowed) are
(a) 216
(b) 375
(c) 400
(d) 720

Answers

Answered by rahulwawle0188
1

a) 216 is the correct option of the following question

Answered by throwdolbeau
5

Answer:

Total number of choices to form 4 digit odd number from the given numbers = 720

Step-by-step explanation:

We know that the odd number always ends with the odd digit number

⇒ Choices for the last digit to form a 4 digit odd number = 4

Choices for the first digit can be any number except 0

⇒ Number of choices for first digit = 5

Also, 2nd digit be any number so no. of choices = 6

Similarly, for 3rd digit, number of choices = 6

Hence, Total number of choices to form 4 digit odd number from the given numbers = 5 × 6 × 6 × 4 = 720

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