Total number of molecules in 10g of calcium carbonate
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No. of moles = given mass of compound / Molar mass
Given mass = 10g
Molar mass = (40 + 12 + 3x16) =100g/mol
No of moles of CaCO3 = 10 / 100 =0.1 mol
According to Avogadro’s law –
1 mol of CaCO3 molecules contains 6.022 x 1023 CaCO3 molecules
Hence, 0.1 mol of CaCO3 molecules will contain 6.022 x 1023x 0.1 molecules
i.e. 0.6022 x 1023 or 6.022 x 1022 molecules
Given mass = 10g
Molar mass = (40 + 12 + 3x16) =100g/mol
No of moles of CaCO3 = 10 / 100 =0.1 mol
According to Avogadro’s law –
1 mol of CaCO3 molecules contains 6.022 x 1023 CaCO3 molecules
Hence, 0.1 mol of CaCO3 molecules will contain 6.022 x 1023x 0.1 molecules
i.e. 0.6022 x 1023 or 6.022 x 1022 molecules
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