Chemistry, asked by n5372466, 1 month ago

total number of molecules in which all the possible bond angle are identical pf3 ,cf4, xef4, PF5,if7,bef2,sp6

Answers

Answered by rishikeshm1912
7

Bond Angles in given molecules

Explanation:

  • According to VSEPR theory, we can find the bond angles in given molecules by determining their geometries and shape or hybridization.
  • Molecule PF₃ has pyramidal geometry. Their is no repulsion of electrons as size of atoms are big so its value of bond angle is 97°.
  • Molecule CF₄ has tetrahedral geometry so it's bond angle is 109.5°.
  • Molecule XeF₄ has square planar shape with hybridization sp³d². It's bond angle is 90° and 180°.
  • Molecule PF₅ has trigonal bipyramidal shape consists of three fluorine atoms occupy equatorial and two occupy axial positions. The bond angle of axial position is 120° and in between equatorial position is 90°.
  • Molecule IF₇ has pentagonal bipyramidal geometry in which there are two angle that are axial angle and equatorial angle. Bond angle of axial position is 90° and of equatorial position is 72°.
  • Molecule BeF₂ has linear shape. Bond angle of BeF₂ is 180°.
  • Molecule SF₆ has octahedral shape with 90° bond angle on equatorial position and 180° bond angle on axial position.

Therefore, two molecule XeF₄ and SF₆ have identical bond angles.

Similar questions