Question

total number of moles present in 12 grams of ozone and 32 grams of SO2 in gaseous mixture would be

Answer 1

Answer:-

0.75 mole

Explanation:-

• Molar mass of Oxygen = 16g/mol

• Molar mass of Sulphur = 32g/mol

Hence, molar mass of Ozone [O₃] :-

= 16×3

= 48g/mol

And, molar mass of SO₂ :-

= 32 + 16×2

= 32 + 32

= 64g/mol

Number of mole in 12g of Ozone :-

= Given Mass/Molar mass

= 12/48

= 0.25 mole

Number of mole in 32g of SO₂ :-

= Given Mass/Molar mass

= 32/64

= 0.5 mole

Total number of mole in the mixture :-

= Mole of Ozone + Mole of SO₂

= 0.25 + 0.5

= 0.75 mole

Thus, total number of moles is 0.75 .