total number of neutrons present in 54ml H2O (l) are
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Number of neutrons in 18 ml or 1 mole = ( 8 ) × NA ( hydrogen has no neutrons )
Therefore number of neutrons In 54 ml or in 3 moles = 3 × 8 = 24 NA( Avogadro number = 6.06.023 × 10^23 )
Hence no. of neutron is 24 in 54ml of water.
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Answer: 24*Na
Explanation:
54 ml h2o = given
density of water = 1gm/ml
mass of h2o = 54*1=54gm
moles = 54/18 = 3.
3*(6.022*10^23)*8 = 24*Na.ANS
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