Question

Total Number of Orbitals Having n+l=3 in cr(24) atom in its ground state..

Answer 1

Answer:

so the combinations are 2p,3s. So 8 electrons. Calculate number of electrons in ground state configuration of Cr(24) with m≠0.

Answer 2

A total number of orbitals having n+l=3 in cr(24) atom in its ground state is two.

• The ground state electronic configuration of Cr is as follows-
• ${1s}^{2} {2s}^{2} {2p}^{6} {3s}^{2} {3p}^{6} {3d}^{4} {4s}^{2}$
• The n is called the principal quantum number and l is called the azimuthal quantum number.
• The value of l for 's' is 0, 'p' is 1 and 'd' is 2.
• For 2p orbital n+l is 2+1=3.
• For 3s orbital n+l is 3+0=3.
• Thus only two orbitals that are 2p and 3s orbital have n+l=3.