Total number of possibilities when 2 dice are thrown together and product is a prime number
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p( prime number as product ) = 3/36 = 1/12
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total number of outcomes=
6×6 =36
total number of favourable outcomes=(2 , 1)
(3,1) (5,1)
=3
p(getting product as a prime no.)=3/36
=1/12
6×6 =36
total number of favourable outcomes=(2 , 1)
(3,1) (5,1)
=3
p(getting product as a prime no.)=3/36
=1/12
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