Question

Total number of protons in 10g of calcium carbonate is

Answer 1

Hey there!

1 mole of Caco3 weighs 100g.

So, 100g of Caco3 contains 6 * 10^23 molecules.

But, We are looking for 10g.

So 100 -> 6 * 10^23
10 -> x

x = 6 * 10^22 molecules.

We know that,
Number of protons in a molecule is directly its atomic number.

So, Ca- 18
C - 6
O - 8 * 3 = 24

Totally, 50 protons and 50 electrons in one molecule of CaCO3

And now,
Number of protons in 10g
= Number of protons in 6 * 10^22 molecules.
= 50 * 6 * 10^22
= 3 * 10^2 * 10^22
= 3 * 10^24 protons.

Therefore, There are 3 * 10^24 protons.

Answer 2

Hey mate!!

Molar mass of CaCO3 = 100 g/mol

Moles = given mass / Molar mass

= 10/100

= 0.1 moles

Moles = no. Of molecules / 6.023 × 10²³

0.1 * 6.023 × 10²³ = no. of molecules

No. of molecules = 6.023 × 10²²

Protons in CaCO3:

Protons in Ca = 20

Protons in C = 6

Protons in O = 8 × 3

Total protons = 50

Total protons in CaCO3 = 50 × 6.023 × 10²²

= 3.0115 × 10²⁴ protons.